Exercise 3.3
1. Find the
quotient and remainder of the following division.
(1) (5x3 - 8x2 + 5x - 7) ÷ (x - 1)
Solution:
________________ |
|- +
|------------------------
| - 3x2 + 5x
| - 3x2 + 3x
| + -
|------------------------
| 2x – 7
| 2x – 2
| - +
|------------------------
| - 5
Quotient = 5x2 – 3x + 2
Remainder = - 5
----------------------------------------------------------------------------------------------------------
(2) (2x2 - 3x - 14) ÷ (x + 2)
Solution:
(i)
2x2/x = 2x
(ii)
2x(x + 2) = 2x2 +4x
(iii)
-7x/x = -7
(iv)
-7(x+2) = -7x – 14
2x - 7
___________ |
| 2x2 +4x
|- -
|--------------------
| -7x – 14
| -7x – 14
| + +
|--------------------
| 0
Quotient = 2x - 7
Remainder = 0
----------------------------------------------------------------------------------------------------------
(3) (9 + 4x + 5x2
+ 3x3 ) ÷ (x + 1)
Solution:
Writing the given polynomial in
descending order, we get
(3x3 + 5x2 + 4x + 9) ÷ (x + 1)
(i)
3x3/x = 3x2
(ii)
3x2(x+ 1) = 3x3 +
3x2
(iii)
2 x2/x = 2x
(iv)
2x(x + 1) = 2 x2 + 2x
(v)
2x/x = 2
(vi)
2(x + 1) = 2x + 2
3x2 + 2x + 2______________ |
| 3x3 + 3x2
| - -
|-------------------------
| 2x2 + 4x
| 2 x2 + 2x
| - -
|-------------------------
| 2x + 9
| 2x + 2
| - -
|-------------------------
| 7
Quotient = 3x2 + 2x + 2
Remainder
= 7
---------------------------------------------------------------------------------------------------------
(4) (4x3
- 2x2 + 6x + 7) ÷ (3 + 2x)
Solution:
Writing the given polynomials in
descending order, we get
(4x3 - 2x2 + 6x + 7) ÷ (2x
+ 3)
(i) 4x3/2x = 2x2
(ii) 2x2(2x + 3) = 4x3 + 6x2
(iii) - 8x2/2x = - 4x
(iv) – 4x(2x + 3) = - 8x2 – 12x
(v) 18x/2x = 9
(vi) 9(2x + 3) = 18x +27
2x2 – 4x + 9
________________ |
| 4x3 + 6x2
|- -
|-----------------------------
| - 8x2 + 6x
| - 8x2 – 12x
| + +
|-----------------------------
| 18x + 7
| 18x +27
| - -
|-----------------------------
| - 20
Quotient
= 2x2 – 4x + 9
Remainder = - 20
-----------------------------------------------------------------------------------------------------------
(5) ( -18
- 9x + 7x2 ) ÷ (x - 2)
Solution:
Writing
the given polynomial in descending order, we get
(7x2
– 9x – 18) ÷ (x – 2)
(i) 7x2/x = 7x
(ii) 7x(x – 2) = 7x2 – 14x
(iii) 5x/x = 5
(iv) 5(x – 2) = 5x - 10
7x + 5
|
x – 2| 7x2 – 9x – 18
| 7x2 – 14x
|- +
|---------------------
| 5x - 18
| 5x - 10
| - +
|----------------------
| - 8
Quotient = 7x + 5
Remainder = - 8
------------------------------------------------------------------------------------------------------------
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